[新しいコレクション] cylinder x^2 y^2=4 167125-Surface area of cylinder x^2+y^2=4

Inside both the cylinder $ x^2 y^2 = 4 $ and the ellipsoid $ 4x^2 4y^2 z^2 = 64 $ Answer $\frac{8 \pi}{3}(6424 \sqrt{3})$ View Answer Related Courses Calculus 3 Calculus Chapter